From a solid sphere of mass M and radius R, a spherical portion of radius R/2 is removed, as shown in the figure. Taking gravitational potential V = 0 at r = ∞ , the potential at the center of the cavity thus formed is: (G = gravitational constant)

Text Solution
Verified by ExpertsThe correct answer is:
B
Potential at point P due to complete solid sphere
= –
= –


= –
= – 
Potential at point P due to cavity part
= –
= 
So potential due to remaining part at point P =
= 
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Two bodies of masses m and 4 m are placed at a distance r. The gravitational potential at a point o…
Two particles of equal mass ‘m’ go around a circle of radius R under the action of their mutual gra…
<p>A satellite is revolving in a circular orbit at a height ‘h’ from the earth’s surface (radius or…
If g E and g m are the accelerations due to gravity on the surfaces of the earth and the moon respe…
A planet in a distant solar system is 10 times more massive than the earth and its radius is 10 tim…
The height at which the acceleration due to gravity becomes (where g = the acceleration due to gra…