A capacitor of capacitance C is charged by charge q 0 . At t = 0, it is connected to a battery of emf V and internal resistance r. Find the charge on the capacitor at time t (positive plate of capacitor connected with positive plate of battery).
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
CV(1 – e –t/Cr ) + q 0 e –t/Cr
Sol.

at time t using KVL
–
– ir + V = 0
⇒ –
r + V = 0
⇒ 
by using integration q = CV (1– e –t/Cr ) + q 0 e –t/Cr – q 0
⇒ So charge on capacitor = q 0 + q = CV(1 – e –t/Cr ) + q 0 e –t/Cr
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