A parallel plate isolated condenser consists of two metal plates of area A and separation 'd'. A slab of thickness 't' and dielectric constant K is inserted between the plates with its faces parallel to the plates and having the same surface area as that of the plates. Find the capacitance of the system. If K = 2, for what value of t/d will the capacitance of the system be 3/2 times that of the condenser with air filling the full space? Calculate the ratio of the energy in the two cases and account for the energy change (assuming q charge on the plate to be constant).
Text Solution
Verified by ExpertsCHECK THE SOLUTION.
C = 
, 
= 
, 
= 
, Δ U = – 
Sol.
C' = 
(i) Without dielectric, C = 
With dielectric, C´ = 
= 
= 
⇒ 
= 
(ii) Energy = 
Energy in 1 st case = E 1 = 
Energy is 2 nd case = E 2 = 
= 
= 
(iii) Δ E = E 2 – E 1 = 
– 
= 
= – 
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