A combination arrangement of the capacitors is shown in the figure
(i) C 1 = 3 µF, C 2 = 6 µF and C 3 = 2 µF then equivalent capacitance between 'a' and 'b' is:
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Ans.
(i)
C ac = 6 + 6 = 12µF
C cb = 
= 6µF
C eq = 
= 4µF
(ii)
Charge on 2µF capacitor
⇒ Q = CV
Q = 2 × 32 = 64µC
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