A capacitor of capacitance 2.0 µF is charged to a potential…

Physics Electrostatics Potential & Capacitance Capacitance MCQ (Single Correct)

A capacitor of capacitance 2.0 µF is charged to a potential difference of 12 V. It is then connected to an uncharged capacitor of capacitance 4.0 µF. Find

the charge flow through connecting wire upto study strate on each of the two capacitors after the connection in µC

The total electrostatic energy stored in both capacitors in µJ

the heat produced during the charge transfer from one capacitor to the other in µJ.

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The correct answer is:

CHECK THE SOLUTION.

[ 16, 48, 96]

Sol. Q = CV = 2 × 12 = 24µC

, Q 1 + Q 2 = 24µC, V = = 4 Volt

Q 1 = 8µC, Q 2 = 16µC

initial charge on 4µF = 0

the charge flow from connecting wire = 16 µC

U 1 = C 1 V 2 = × 2 × 2 = 16µJ

U 2 = C 2 V 2 = × 4 × 2 = 32µJ

Total energy stored = 48 µJ

Δ H = (U i )system – (U f ) system f = × 2 × 12 2 – (16 + 32) = 96µJ

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