Published by:
CGP EDU Academic Team
Published on: September 13, 2026
The equivalent capacitance of the combination shown in the figure between the indicated points is given by 
µF. then find the value of n.
Correct Matrix Matching
Text Solution
Verified by ExpertsThe correct answer is:
(i) from loop AB EFA AB EFA ls ; (ii) from loop ABCA AB CA l ; (iii) from ; (i), ; (ii) and ; (iii) we get q 1
(20µF)
Sol. Charge on capacitor is assume as according to reverse symmetry.
q 1 + q 2 = C eq V.....(i)
from loop AB EFA AB EFA ls
– 
= 0
⇒ 2q 2 – 3 q 1 = 0 .....(ii)
from loop ABCA AB CA l
– 
+ V = 0
⇒ 4V = 2q 1 + q 2 .....(iii)
from (i), (ii) and (iii) we get
q 1 + 
= C eq 
⇒ C eq = 
µF
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