here conducting plates of area 500 cm 2 area kept fixed as shown. Distance between adjacent plates is 8.85 mm. A charge of 1.0 nC is placed on the middle plate.
A
The charge on the outer surface of the upper plate is given by n×10 – 11 C then find the value of n.
B
Find the potential difference (inV) developed between the upper and the middle plates. 
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
[ 50, 10]
Sol. Charge after distribution
charge on outer plate = 
;
C = 
= 50 pF
charge on outer surface of upper plate is = 
= 0.5nC Ans
V = 
= 10V Ans
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