On a parallel plate capacitor following operations can be p…

Physics Electrostatics Potential & Capacitance Capacitance MCQ (Single Correct)

On a parallel plate capacitor following operations can be performed.

(P) – connect the capacitor to a battery of emf V

(Q) – disconnect the battery

(R) – reconnect the battery with polarity reversed

(S) – insert a dielectric slab in the capacitor

In PQR (perform P, then Q, then R), the stored electric energy remains unchanged and no thermal energy is developed

The charge appearing on the capacitor is greater after the action PSQ then after the action PQS

The electric energy stored in the capacitor is greater after the action SPQ then after the action PQS

The electric field in the capacitor after the action PS is the same as that after SP

Text Solution

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The correct answer is:

CHECK THE SOLUTION.

(b, c, d)

In PQS process charge on capacitor is Q = CV

In PSQ process charge on capacitor is Q' = KCV

Electric energy stored in PQS is = CV 2

Electric energy stored in PSQ is = KCV 2

U PSQ > U PQS

Electric field in PS is E =

Electric field in SP is E =

E PS = E SP

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