Physics Electrostatics Potential & Capacitance JEE (Main) / AIEEE Problems Previous Years - ( Capacitance ) Comprehension (MCQ)

Consider a simple RC circuit as shown in figure 1.

Process 1: In the circuit the switch S is closed at t = 0 and the capacitor is fully charged to voltage V 0 (i.e., charging continues for time T>> RC). In the process some dissipation (E D ) occurs across the resistance R. The amount of energy finally stored in the fully charged capacitor is E C .

Process 2: In a different process the voltage is first set to and maintained for a charging time
T >>RC. Then the voltage is raised to without discharging the capacitor and again maintained for a time T >> RC. The process is repeated one more time by raising the voltage to V 0 and the capacitor is charged to the same final voltage V 0 as in Process 1.

These two processes are depicted in figure 2.

(i) In process 1, the energy stored in the capacitor E C and heat dissipated across resistance E D are related by:

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The correct answer is:
CHECK THE SOLUTION.

(i)

Sol. E C = ; E D = V 0 CV 0 –

=

∴ E C = E D

(ii)

Sol. =

=

=

=

=

Total =

=

E D =

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