A capacitance of 2µF is required in an electrical circuit across a potential difference of 1.0 kV. A large number of 1µF capacitors are available which can withstand a potential difference of not more than 300 V. The minimum number of capacitors required to achieve this is:
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As each capacitors cannot withstand more than 300 V , so there should be four capacitors in each row became in this condition 1 kV i.e. 1000 V will be divided by a (i.e., 250 not more than 300 V ).
Now, equivalent capacitance of one row
Now, we need equivalent of 
, so let we need n such rows
[ 
in parallel combination 
]
Total number of capacitors 
number of rows 
number of capacitors in each row
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