An electric field of 20 N/C exists along the negative x-axis in space. Calculate the potential difference V B – V A , where the points A and B are given by:.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
[ 0, E.d = 40 V]
Sol.
∴ 
∴ A and B at same potential
∴ V B – V A = 0
∴ Against the field potential rises
∴ V B – V A = E λ = 20 × 2 = 40 V
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
If we move in a direction opposite to the electric lines of force:
The distance between two plates is 2 cm, when an electric potential of 10 volt is applied between t…
In electrostatics the potential is equivalent to -
The potential due to a point charge at distance r is -
An object is charged with positive charge. The potential at that object will be -
Two points (0, a) and (0, -a) have charges q and -q respectively then the electrical potential at o…