A particle of charge + 3 x 10 -9 C is in a uniform field directed to the left. It is released from rest and moves a distance of 5 cm, after which its kinetic energy is found to be 4.5 x 10 -5
Text Solution
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CHECK THE SOLUTION.
[ + 4.5 × 10 -5 J
3 × 10 5 N/C
1.5 x 10 4 V]
Sol.
W elec = Δ K = 4.5 × 10 –5 J.
W elec = qEr = 4.5 × 10 –5 E = 
= 3 × 10
5 N/C
V A – V B = Er = 3.0 × 10 5 × 0.05 = 1.5 × 10 4 V
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