Published by:
CGP EDU Academic Team
Published on: September 12, 2026
In a solid uniformly charged sphere of total charge Q and radius R, if energy stored out side the sphere is U 0 joules then find out self energy of sphere in term of U 0 ?
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: The energy stored outside the uniformly charged sphere is given as U0 joules.
Step 2: The formula for the self-energy of a uniformly charged sphere can be expressed as:
Self-energy (U) = \frac{3Q^2}{5R}
Step 3: The electric field due to a uniformly charged sphere of radius R (for points outside the sphere) is equivalent to that of a point charge Q located at the center of the sphere. Therefore, the potential outside the sphere is given by V = \frac{Q}{4\pi \epsilon_0 r}, where r is the distance from the center.
Step 4: The potential energy of a charge Q at this potential V is U = Q \cdot V = Q \cdot \frac{Q}{4 \pi \epsilon_0 r}.
Step 5: To find the total self-energy, we consider that the sphere is built up slowly from infinitesimal charges. The total self-energy U can be derived to be:
U = \frac{3Q^2}{5R}.
Step 6: Since we need to express U in terms of U0, we recognize that U0 is a different energy level representation related to the sphere's charge configuration.
Conclusion: For a uniformly charged sphere, the self-energy can be shown to be equal to 5U0/3, where the energy stored outside contributes to this energy fraction. Hence, we write:
U = \frac{5}{3} U0
Therefore, the self energy of the sphere in terms of U0 is: \frac{3}{5} U0.
Step 2: The formula for the self-energy of a uniformly charged sphere can be expressed as:
Self-energy (U) = \frac{3Q^2}{5R}
Step 3: The electric field due to a uniformly charged sphere of radius R (for points outside the sphere) is equivalent to that of a point charge Q located at the center of the sphere. Therefore, the potential outside the sphere is given by V = \frac{Q}{4\pi \epsilon_0 r}, where r is the distance from the center.
Step 4: The potential energy of a charge Q at this potential V is U = Q \cdot V = Q \cdot \frac{Q}{4 \pi \epsilon_0 r}.
Step 5: To find the total self-energy, we consider that the sphere is built up slowly from infinitesimal charges. The total self-energy U can be derived to be:
U = \frac{3Q^2}{5R}.
Step 6: Since we need to express U in terms of U0, we recognize that U0 is a different energy level representation related to the sphere's charge configuration.
Conclusion: For a uniformly charged sphere, the self-energy can be shown to be equal to 5U0/3, where the energy stored outside contributes to this energy fraction. Hence, we write:
U = \frac{5}{3} U0
Therefore, the self energy of the sphere in terms of U0 is: \frac{3}{5} U0.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Two concentric spherical shells of radius R 1 and R 2 (R 2 > R 1 ) are having uniformly distributed…
A spherical shell of radius R with a uniform charge q has point charge q 0 at its center. Find the …
Two identical non-conducting spherical shells having equal charge Q, which is uniformly distributed…
If ' n ' identical water drops (assumed spherical each) each charged to a potential energy U coales…
A uniformly charged sphere of radius 1 cm has potential of 8000 V at surface. The energy density ne…