A bullet of mass m moving vertically upwards instantaneously with a velocity 'u' hits the hanging block of mass 'm' and gets embedded in it, as shown in the figure. The height through which the block rises after the collision. (assume sufficient space above block) is :
Text Solution
Verified by ExpertsThe correct answer is:
C
From momentum conservation
mu = 2mv ⇒ v = 
from energy conservation
× 2m × 
= 2 mgh ⇒ h = 
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