A small sphere of radius R is held against the inner surface of a larger sphere of radius 6R. The masses of large and small spheres are 4M and M respectively. This arrangement is placed on a horizontal table as shown. There is no friction between any surfaces of contact. The small sphere is now released. The coordinates of the centre of the large sphere when the smaller sphere reaches the other extreme position is :
Text Solution
Verified by ExpertsB
Since all the surfaces are smooth, no external force is acting on the system in horizontal direction.
Therefore, the centre of mass of the system in horizontal direction remains stationary.
x-coordinate of COM initially will be given be given by–
x i = 
= 
= (L + R) ....(1)
Let (x,0) be the coordinates of the centre of large sphere in final position. Then x-coordinate of COM finally will be
= 
= ( x– R ) ............. (2).
Equating (1) and (2), we have
Therefore, coordinates of large sphere, when the smaller sphere reaches the other extreme position, are (L + 2R, 0)
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems