A skater of mass m standing on ice throws a stone of mass M with a velocity v in a horizontal direction. The distance, skater will move back is (the coefficient of friction between the skater and the ice is μ ) :
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
C
P i = 0 ...(i)
P f = MV – mV 1 ....(ii)
MV – mV 1 = 0 ⇒ u = 
V
Using V 1 2 = u 2 + 2ax ⇒ a = μ g
= 0 + 2 μ g x ∴ x = 
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