A man of mass 60 kg start falling from building of height 80 m with a bag of 2 kg in his hand. After falling through a distance 20 m he throw the bag horizontally with respect to him so that he fall in a pond 2m away from the vertical lines of fall. Calculate horizontal distance of bag from the vertical line of fall where it lands. (take g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(60)
T = 
= 
= 
= 4s
t = 
= 
= 
= 2s
Δ t = T – t = 4 – 2 = 2 s
V = 
= 
= 1 m/s
Mv = mv
v = 
= 30 m/s
R = v Δ t = 30 × 2 = 60 m
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