The force of repulsion between two identical positive charges when kept with a separation in air is F Half the gap between the two charges is filled by a dielectric slab of dielectric constant 4. Then the new force of repulsion between those two charges becomes
A
B
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D
Text Solution
Verified by ExpertsThe correct answer is:
D
Let q be each charge.
According to Coloumb's law, the force of repulsion between the two charges when kept in air is
When half of the gap between the two charges is filled with the dielectric slab of dielectric constant , the new force of repulsion between them becomes
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