Published by:
CGP EDU Academic Team
Published on: September 11, 2026
A train is moving slowly on a straight track with a constant speed of . A passenger in that train starts walking at a steady speed of
to the back of the train in the opposite direction of the motion of the train. So to an observer standing on the platform directly in front of that passenger, the velocity of the passenger appears to be
A
B
C
D
zero
Text Solution
Verified by ExpertsThe correct answer is:
C
Step 1: Identify the speeds involved. Let the speed of the train be denoted as $v_t$ and the speed of the passenger walking in the opposite direction as $v_p$.
Step 2: Since the passenger is walking towards the back of the train, the effective speed of the passenger relative to an observer on the platform is the speed of the train minus the speed of the passenger. Thus, the apparent speed of the passenger is $v_t - v_p$ and is in the opposite direction of the train's movement.
Step 3: Conclude that to an observer on the platform, the velocity of the passenger appears to be $v_t - v_p$ in the opposite direction of the train.
Therefore, the correct answer is Option C.
Step 2: Since the passenger is walking towards the back of the train, the effective speed of the passenger relative to an observer on the platform is the speed of the train minus the speed of the passenger. Thus, the apparent speed of the passenger is $v_t - v_p$ and is in the opposite direction of the train's movement.
Step 3: Conclude that to an observer on the platform, the velocity of the passenger appears to be $v_t - v_p$ in the opposite direction of the train.
Therefore, the correct answer is Option C.
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