In a radioactive decay, an element 
emits four 
-particles, three 
-particles and eight gamma photons. The atomic number and mass number of the resulting final nucleus are
Text Solution
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Emission of 
-particle decreases the atomic number and mass number by 2 and 4 respectively. Emission of 
-particle increases the atomic number by 1 while the mass number remains unchanged. Emission of 
-particle both the atomic number and the mass number remain unchanged.
After the emission of four 
-particles, three 
-particles and eight 
photons,
Decrease in atomic number 
Decrease in mass number 
Thus, the atomic number and mass number of resulting final nucleus are 
and 
respectively.
The resulting final nucleus is 
.
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