Published by:
CGP EDU Academic Team
Published on: September 12, 2026
A rectangular block of mass 5 kg attached to a horizontal spiral spring executes simple harmonic motion of amplitude 1 m and time period 3.14 s. The maximum force exerted by spring on block is___N.
Text Solution
Verified by ExpertsThe correct answer is:
20
(20)
By Newton's second law,
F = ma max .
The maximum acceleration for a SHM is given by
a max = ω 2 A ...(i)
The time period is given by
T= 
= 3.14s
Thus, the maximum acceleration from equation (i)
The maximum force is
F = 5 kg x 4 m s -2 = 20 N
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