In the given figure the total charge stored in the combination of capacitors is 100 µC. The value of ‘x’ is______________.
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(5)
All the capacitors are in parallel combination and therefore potential drop across each capacitor would be the same.
Charge on the capacitor can be written as, Q = CV.
The charge on C 1 is Q 1 = 2 x 10 = 20 µC
The charge on C 2 is Q 2 = x x 10 = 10 x µC
The charge on C 3 is Q 3 = 3 x 10 = 30 µC
By the given data.
C 1 + C 2 + C 3 = 100 µC
10(2 +x + 3) = 100
x = 5
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A parallel plate capacitor with air between the plate has a capacitance of 15pF. The separation bet…
A capacitor has capacitance 5µF when it's parallel plates are separated by air medium of thickness …
A capacitor of capacitance 900µF is charged by a 100 V battery. The capacitor is disconnected from …
Two parallel plate capacitors C 1 and C 2 each having capacitance of 10µF are individually charged …
A charge particle of 2µC accelerated by a potential difference of 100V enters a region of uniform m…
A parallel plate capacitor with plate area A and plate separation d is filled with a dielectric mat…