Physics Electrostatics Potential & Capacitance JEE Main 2023 - ( Electrostatics ) MCQ (Single Correct)

An electric dipole of dipole moment is 6. 0 x 10 -6 C m placed in a uniform electric field of 1.5 x 10 3 N C -1 in such a way that dipole moment is along electric field. The work done in rotating dipole by 180° in this field will be_______mJ.

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The work done for rotating a dipole is given by the change in the potential energy. The potential energy is given by

So, the work done is

W= -pEcos 180° - (-pEcos0°) = 2pE

= 2 x 6 x 10 6 x l.5 x 10 3 = 18mJ

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