A proton with a kinetic energy of 2.0 eV moves into a region of uniform magnetic field of magnitude 
x 10 -3 T. The angle between the direction of magnetic field and velocity of proton is 60°. The pitch of the helical path taken by the proton is____cm. (Take, mass of proton = 1. 6 x 10 -27 kg and charge on proton = 1.6 x 10 -19 C).
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(40)
The given data is
K. E = 2 eV
B = 
x 10 -3 T
= 60 0
The pitch of the proton is given by
…(i)
By using
Substituting the values in equation (i)
= 2 x 2 x 10 -1 = 0.4 m = 40 cm
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