A semicircular wire is uniformly charged with linear charge density dependent on the angle θ from y ‐direction as
, where
is a constant. The electric field intensity at the centre of the arc is

Text Solution
Verified by ExpertsThe correct answer is:
B
Lets take an element at angle θ with vertical, subtending dθ angle electric field due to this element


horizontal component
will be cancelled out with opposite element, and
components get added up
So 

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