A charged particle of charge Q is held fixed and another charged particle of mass ‘m’ and charge ‘q’ (of the same sign) is released from a distance r'. The impulse of the force exerted by the external agent on the fixed charge by the time distance between ‘Q’ and ‘q’ becomes 2r is
A
B
C
0
D
cannot determine
Text Solution
Verified by ExpertsThe correct answer is:
B
Applying conservation of energy, we get
Force required to keep Q fixed = Coulombic repulsion between the charges
= Force on charge q
Impulse = change in momentum of
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