A non‐planar loop of conducting wire carrying a current 
is placed as shown in the figure. Each of the straight sections of the loop is of length 
. The magnetic field due to this loop at the point 
points in the direction
Text Solution
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The magnetic field at 
due to the loop is equal to the vector sum of the magnetic fields produced by loops ABCDA and AFEBA as shown in the figure.
Magnetic field due to loop ABCDA will be along 
and due to loop AFEBA, along 
. Magnitude of magnetic field due to both the loops will be equal.
Therefore, direction of resultant magnetic field at 
will be 
.
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