In the figure shown a lift goes downwards with a constant retardation. An observer in the lift observers a conical pendulum in the lift, revolving in a horizontal circle with time period 2 seconds. The distance between the center of the circle and the point of suspension is 2.0 m. Find the retardation of the lift in m/s 2 .
Use 
2 = 10 and g = 10 m/s 2
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
T = 2 π 
= 2 π 
g eff. = g + a; T = 2 put ⇒ g eff = 20 ⇒ g + a = 20 ⇒ a = 10 m/s 2 .
Ans. Retardation = 10 m/s 2
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