D

Step 1: Identify the circuit configuration
We have two branches of resistors and current sources. The left branch has a 5 Ω resistor and a 10 Ω resistor in series, while the right branch has a 1 Ω and a 2 Ω resistor in series with the 5 A current source.

Step 2: Analyze the left branch
The total resistance of the left branch:
R_left = 5 Ω + 10 Ω = 15 Ω.
In this branch, the current from the current source is 10 A. The voltage across the 10 Ω resistor can be calculated using Ohm's Law:
V_{10Ω} = I imes R = 10 A imes 10 Ω = 100 V.

Step 3: Analyze the right branch
The total resistance of the right branch:
R_right = 1 Ω + 2 Ω = 3 Ω.
The current through the right branch (with the 5 A source) is 5 A. The voltage drop across the 2 Ω resistor:
V_{2Ω} = I imes R = 5 A imes 2 Ω = 10 V.

Step 4: Determine the total voltage across the parallel branches
In parallel circuits, the voltage across each branch is equal. Therefore, since we found the voltage across the left branch with the 10 Ω resistor to be 100 V, we conclude that:
V_{across 10Ω} = 100 V.

Step 5: Calculate the current passing through the 10 Ω resistor
The current through the 10 Ω resistor is equal to the current from the source, which is 10 A.

Final result:
Voltage across the 10 Ω resistor is 100 V and the current passing through it is 10 A.