A 100 W bulb B 1 and two 60 W bulbs B 2 and B 3 are connected to a 250 V source as shown in the figure. Now W 1 , W 2 and W 3 are the output powers of the bulbs B 1 , B 2 and B 3 respectively. Then:
Text Solution
Verified by ExpertsThe correct answer is:
D
P = 
so R = 
∴ R 1 = 
and R 2 = R 3 = 
Now W 1 = 
· R 1
W 2 = 
· R 2
and W 3 = 
W 1 : W 2 : W 3 = 15 : 25 : 64
or W 1 < W 2 < W 3
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
A wire has a resistance of 12 ohms. If it is bent in the form of a circle. The effective resistance…
A wire has a resistance 12 ohms. if it is bent in the form of a equilateral triangle. The resistanc…
There are five resistances of 1 ohm each. If the initial three resistance are joined in parallel an…
For the network of resistance shown in the figure the equivalent resistance of the network between …
If 2 bulbs rated 2.5 W – 110 V and 100 W – 110 V are connected in series to a 220 V supply then
A 50 W bulb is in series with a room heater and the combination is connected across the mains. To g…