Figure shows an arrangement to measure the emf ε and internal resistance r of a battery. The voltmeter has a very high resistance and the ammeter has a very small resistance. The voltmeter reads 1.52 V when the switch S is open. When the switch is closed the voltmeter reading drops to 1.45 V and the ammeter reads 1.0 A. The internal resistance of the battery in m Ω Ω will be?
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(70 m Ω Ω )
Sol. E = 1.52 V
V = E – ir
1.45 = 1.52 – 1r
r = 0.07 Ω Ω
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