A

Step 1: Convert the mass of the block into kilograms. The mass is given as 500 g, which is equal to 0.5 kg.
Step 2: Identify the forces acting on the block. The weight of the block ($W$) can be calculated using the formula:
$W = mg$, where $m = 0.5 ext{ kg}$ and $g = 10 ext{ m/s}^2$. So,
$W = 0.5 imes 10 = 5 ext{ N}$.
Step 3: The component of weight acting down the incline ($W_{ ext{down}}$) is given by:
$W_{ ext{down}} = W imes ext{sin}( heta)$, where $ heta = 53°$. Therefore,
$W_{ ext{down}} = 5 imes ext{sin}(53°)$. The value of $ ext{sin}(53°)$ is approximately 0.798.
Thus, $W_{ ext{down}} = 5 imes 0.798 ext{ N} ext{ approximately } 3.99 ext{ N}$.
Step 4: Since the block moves with uniform speed, the frictional force ($F_{friction}$) must balance the downhill component of the weight. Hence,
$F_{friction} = W_{ ext{down}} ext{ approximately } 3.99 ext{ N}$.
Step 5: Calculate the work done against friction ($W_f$) over a distance of 2 m:
$W_f = F_{friction} imes ext{distance} = 3.99 ext{ N} imes 2 ext{ m} = 7.98 ext{ J}$.
Conclusion: The work done against friction is 7.98 J.