B

Step 1: Calculate the work done by the net force.
The net force acting on the particle is the applied force minus the frictional force:
\( F_{net} = F_{applied} - F_{friction} = 1000 \, \text{N} - 10 \, \text{N} = 990 \, \text{N} \)

Step 2: Calculate the work done on the particle using the formula:
\( W = F_{net} \cdot d \)
where \( d = 4 \, \text{m} \). Therefore:
\( W = 990 \, \text{N} \times 4 \, \text{m} = 3960 \, \text{J} \)

Step 3: Calculate the change in kinetic energy. The initial velocity \( u = 1 \, \text{m/s} \) and the final velocity \( v = 10 \, \text{m/s} \). The change in kinetic energy is given by:
\( \Delta KE = \frac{1}{2} m v^2 - \frac{1}{2} m u^2 = \frac{1}{2} m (v^2 - u^2) \)
Calculating the change in kinetic energy:
\( \Delta KE = \frac{1}{2} m (10^2 - 1^2) = \frac{1}{2} m (100 - 1) = \frac{1}{2} m (99) = 49.5m \)

Step 4: Setting the work done equal to the change in kinetic energy:
\( W = \Delta KE \Rightarrow 3960 = 49.5m \)

Step 5: Solve for the mass \( m \):
\( m = \frac{3960}{49.5} \approx 80 \, \text{kg} \)

Therefore, the mass of the particle is approximately 80 kg.