As shown in figure, there is pulley block system. The system is released from rest and the block of mass 2kg is found to have a speed 0.3 m/s after it has descended through a distance of 2m. Find the coefficient of kinetic friction between the block and the table. (g = 10 m/s 2 )
Text Solution
Verified by ExpertsThe correct answer is:
CHECK THE SOLUTION.
(µ = 0.245)
Sol. Displacement of 4kg block = 2 × 2m = 4m
Final speed of 4kg block = 2 × 0.3 = 0.6 m/s
W f + W g = 
K
⇒ –µ × 4 × 10 × 4 + 2 × 10 × 2 = 
× 4 × (0.6) 2 + 
× 2 × (0.3) 2
⇒ 160 
= 40 – (0.72 + 0.09) ⇒ µ = 
= 0.2449
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