A particle moves with deceleration along the circle of radius R so that at any
moment of time its tangential and normal accelerations are equal in magnitude. At the initial moment 
the speed of the particle equals 
, then :
(i) the speed of the particle as a function of the distance covered 
will be
A
B
C
D
Text Solution
Verified by ExpertsThe correct answer is:
A
(i) deceleration of particles
– 
= 
⇒ – 
= 
Integrating both side
= 
⇒ – 
= 
v = v 0 e –s/R
(ii) |a t | = a C
a = 
a C = 
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