Published by:
CGP EDU Academic Team
Published on: September 12, 2026
Two rods of the same length and areas of cross-section
and
have their ends at the same temperature
and
are the thermal conductivities of the two rods. The rate of flow of heat is same in both rods if
Text Solution
Verified by ExpertsThe correct answer is:
A
Step 1: The rate of heat flow through a rod can be expressed using Fourier's law of heat conduction: \[ Q = \frac{KA(\Delta T)}{L} \] where \( Q \) is the heat transfer per unit time, \( K \) is the thermal conductivity, \( A \) is the cross-sectional area, \( \Delta T \) is the temperature difference, and \( L \) is the length of the rod.
Step 2: Given that both rods have the same length and temperature difference at their ends, we can equate the heat conduction rates for both rods: \[ Q_1 = Q_2 \]. Thus, we have:
\[ \frac{K_1 A_1 (T_1 - T_2)}{L} = \frac{K_2 A_2 (T_1 - T_2)}{L} \]
Step 3: Simplifying, we cancel out the common factors and rearranging gives us the relationship:
\[ \frac{A_1}{A_2} = \frac{K_2}{K_1} \] (this is the first option given).
Therefore, A.
Step 2: Given that both rods have the same length and temperature difference at their ends, we can equate the heat conduction rates for both rods: \[ Q_1 = Q_2 \]. Thus, we have:
\[ \frac{K_1 A_1 (T_1 - T_2)}{L} = \frac{K_2 A_2 (T_1 - T_2)}{L} \]
Step 3: Simplifying, we cancel out the common factors and rearranging gives us the relationship:
\[ \frac{A_1}{A_2} = \frac{K_2}{K_1} \] (this is the first option given).
Therefore, A.
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