Match the List-I with List-II.
List-I | List-II | ||||||||||
A. | Wurtz reaction | (i) |
| Electrophilic addition | reaction | ||||||
Electrophilic addition | |||||||||||
reaction | |||||||||||
B. |
| Hydration of | alkenes | (ii) |
| Nucleophilic | substitution reaction | ||||
Hydration of | |||||||||||
alkenes | |||||||||||
Nucleophilic | |||||||||||
substitution reaction | |||||||||||
C. | Nitration of alkanes | (iii) |
| Free radical | substitution | ||||||
Free radical | |||||||||||
substitution | |||||||||||
D. |
| Reaction of alkene | with NBS | (iv) |
| Electrophilic | substitution reaction | ||||
Reaction of alkene | |||||||||||
with NBS | |||||||||||
Electrophilic | |||||||||||
substitution reaction |
Choose the correct answer from the options given below.
Text Solution
Verified by ExpertsC
Wurtz reaction is a nucleophillic substitution reaction as it involves exchange of halogen and metal with the involvement of radical species
to form
bond.

Hydration of alkene involves act of adding electrophillic hydrogen on nucleophillic alkenes. So, it is a electrophillic addition reaction.

Nitration of alkane involves substitution of
from alkene by a nitro group (electrophile). So, it is a electrophillic substitution reaction.
Reaction of alkene with NBS involves formation of free radical
from NBS reagent and hydrogen atom at allylic position will get substitution by bromine radical. So, it is a type of free radical substitution reaction.
Hence, the correct match is A-(ii), B-(i), C-(iv), D-(iii).
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