Published by:
CGP EDU Academic Team
Published on: September 12, 2026
The initial speed of a bullet fired from a rifle is
. The rifle is fired at the centre of a target
away at the same level as the target. How far above the centre of the target?
Text Solution
Verified by ExpertsThe correct answer is:
C
To find out how high above the center of the target the bullet will strike, we can use the equations of motion under gravity.
Given:
Initial speed of bullet, v = 630 m/s
Distance to target, d = 700 m
Acceleration due to gravity, g = 9.81 m/s²
Step 1: Calculate the time taken to reach the target.
Using the formula:
$$ t = \frac{d}{v} $$
Substituting the values:
$$ t = \frac{700}{630} = 1.111 \text{ seconds} $$
Step 2: Now, calculate the vertical displacement using the formula for free fall:
$$ h = \frac{1}{2} g t^2 $$
Substituting the time value:
$$ h = \frac{1}{2} \times 9.81 \times (1.111)^2 \approx 6.1 \text{ m} $$
Conclusion: The bullet will strike about 6.1 m above the center of the target. Hence, Option C is correct.
Given:
Initial speed of bullet, v = 630 m/s
Distance to target, d = 700 m
Acceleration due to gravity, g = 9.81 m/s²
Step 1: Calculate the time taken to reach the target.
Using the formula:
$$ t = \frac{d}{v} $$
Substituting the values:
$$ t = \frac{700}{630} = 1.111 \text{ seconds} $$
Step 2: Now, calculate the vertical displacement using the formula for free fall:
$$ h = \frac{1}{2} g t^2 $$
Substituting the time value:
$$ h = \frac{1}{2} \times 9.81 \times (1.111)^2 \approx 6.1 \text{ m} $$
Conclusion: The bullet will strike about 6.1 m above the center of the target. Hence, Option C is correct.
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