A short circuited coil is placed in a time-varying magnetic field. Electrical power is dissipated due to the current induced in the coil. If the number of turns were to be four times and the wire radius halved keeping the radius of the loop unchanged, the electrical power dissipated would be:
Text Solution
Verified by ExpertsThe correct answer is:
B
Power P = 
here e = induced emf = – 
Where φ φ = NBA
∴ e = – NA 
also R ∝ 
where R = resistance, r = radius, λ = length
∴ P ∝ 
∴ 
= 1
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