An inductor of inductance L = 400 mH and resistors of resistances R 1 = 2 Ω Ω and R 2 = 2 Ω Ω are connected to a battery of emf 12 V as shown in the figure. The internal resistance of the battery is negligible. The switch S is closed at t = 0. The potential drop across L as a function of time is:
A
B
C
12 e –5t V
D
6 e –5t V
Text Solution
Verified by ExpertsThe correct answer is:
C
V L = εe – 
= 12.e – 
= 12 e –5t .
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