The second’s hand of a watch has length 6 cm. Speed of end point and magnitude of difference of velocities at two perpendicular positions will be :
A
2π & 0 mm/s
B
& 4.44 mm/s
C
& 2π mm/s
D
2π & 
mm/s
mm/s
Text Solution
Verified by ExpertsThe correct answer is:
D
ω second = 
= 
rad/sec.
v = ω.r = 
× 0.06 m/s = 2π mm/s
= 
v = 2 
π mm/s
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