Home Physics Motion in a Plane NEET Previous Year Question The position vector of a particle as a func…
Physics Motion in a Plane NEET Previous Year Question MCQ (Single Correct)

The position vector of a particle as a function of time is given by:

= 4sin(2πt) + 4cos(2πt)

Where R is in meters, t is seconds and and denote unit vectors along x-and y-directions, respectively. Which one of the following statements is wrong for the motion of particle?

A
Magnitude of acceleration vector is , where v is the velocity of particle
B
Magnitude of the velocity of particle is 8 meter/second
C
path of the particle is a circle of radius 4 meter.
D
Acceleration vector is along -

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The correct answer is:
B

x = 45 m 2πt, y = 4 cos (2πt)

Squiring and adding x 2 + y 2 = 4 2 ⇒ R = 4

⇒ Circular motion

V = ωR = (2π) = 8π

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