A particle of mass 10 g moves along a circle of radius 6.4 cm with a constant tangential acceleration. What is the magnitude of this acceleration if the kinetic energy of the particle becomes equal to 8 × 10 –4 J by the end of the second revolution after the beginning of the motion ?
Text Solution
Verified by ExpertsThe correct answer is:
B
W all = KE
(ma t )(s) = 
mv 2
(10 × 10 –3 )(a t ) (4π × 6.4 × 10 –2 ) = 8 × 10 –4
⇒ a t = 0.1 m/s 2
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