A ball of mass 3 kg moving with a speed of 100 m/s, strikes a wall at an angle 60º (as shown in figure). The ball rebounds at the same speed and remains in contact with the ball for 0.2 s, the force exerted by the ball on the wall is : 
N
N
Text Solution
Verified by ExpertsA
The force imparted by the bali is equal to rate of change of linear momentum.
The vector 
represents the momentum of the ball before the collision and the vector 
that after the collision. The vector 
represents the change in momentum of the ball 
.
As the magnitue of 
and 
are equal the components of 
and 
along the wall are equal and in the same direction while those perpendicular to the wall are equal and opposite. Thus, the change in momentum id due only to the change in direction of the perpendicular components.
Hence 
= OA sin 60º – (–OB sin 60º)
= mv sin 60º + mv sin 60º
= 2mv sin 60º
= 2 × 3 × 100 × 
= 300 
kg-m/s
The force exerted on the wall
F = 
= 
= 1500 
N
Note : 
is directed perpendicular and away from the plate.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems