A parallel plate capacitor of capacitance 
is charged by a battery connected between its plates to potential difference of 
. The battery is now disconnected and a dielectric slab 
is inserted between the plates. The change in its potential energy after inserting the dielectric slab is____J.
Text Solution
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Before inserting dielectric capacitance is given 
and charge on the capacitor 
After inserting dielectric capacitance will become 
.
Change in potential energy of the capacitor
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