Amplification factor of a triode is 10. When the plate potential is 200 volt and grid potential is – 4 volt, then the plate current of 4mA is observed. If plate potential is changed to 160 volt and grid potential is kept at – 7 volt, then the plate current will be
Text Solution
Verified by ExpertsThe correct answer is:
A
⇒ ⇒ 4 = k (200 – 10 × × 4) 3/2 = k × × (160) 3/2 ….(i)
and 
….(ii)
From equation (i) and (ii) we get
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