Home Physics Units, Dimensions and Measurement Matching Type Question Match the physical quantities given in colum…
Physics Units, Dimensions and Measurement Matching Type Question Single Correct MCQ
Published on: September 12, 2026

Match the physical quantities given in column I with dimensions in column II.

Column-I

Column-II

(i) Torque

(p) 

(ii) Angular momentum

(q) 

(iii) Latent heat

(r) 

(iv) Surface tension

(s) 

(v) Light year

(t) 

(u) 

A
(i)-(t) (ii)-(p) (iii)-(q) (iv)-(u) (v)-(s)
B
(i)-(q) (ii)-(r) (iii)-(p) (iv)-(t) (v)-(s)
C
(i)-(q) (ii)-(p) (iii)-(t) (iv)-(r) (v)-(s)
D
(i)-(t) (ii)-(s) (iii)-(q) (iv)-(p) (v)-(r)

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Text Solution

Verified by Experts
The correct answer is:
B
Let's analyze each quantity in Column I and match it with the appropriate dimensions in Column II:
(i) Torque: Torque is given by the formula \( \tau = r \times F \). Dimensions of torque are \( [M][L^2][T^{-2}] = [ML^2T^{-2}] \). Therefore, it matches with (q).
(ii) Angular momentum: Angular momentum is given by \( L = r \times p \) where \( p \) is momentum. The dimensions are also \( [M][L^2][T^{-1}] = [ML^2T^{-1}] \). Therefore, it matches with (p).
(iii) Latent heat: Latent heat is defined as the heat absorbed/released per unit mass. The dimensions are \( [M^0][L^2][T^{-2}] = [M^0L^2T^{-2}] \). Therefore, it matches with (r).
(iv) Surface tension: Surface tension is defined as force per unit length, which has dimensions \( [M^0][L^1][T^{-2}] = [M^0LT^{-2}] \). Therefore, it matches with (s).
(v) Light year: A light year is a unit of distance, with dimensions given as \( [M^0][L^1][T^0] = [M^0L^1T^0] \). Therefore, it matches with (t).
Thus, we have: \( (i)-(q), (ii)-(p), (iii)-(r), (iv)-(s), (v)-(t) \) which corresponds to Option B.

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