Published by:
CGP EDU Academic Team
Published on: September 12, 2026
In a vernier callipers, the smallest division of main scale is 1 mm. Vernier scale has 20
divisions which coincide with 19 divisions of main scale. When fixed jaw touches a movable jaw, zero of vernier scale lies on right of zero of the main scale and
division of vernier scale coincides with any division of main scale. Type of zero error and its value is
Text Solution
Verified by ExpertsThe correct answer is:
C
Step 1: Identify the main scale division (MSD) and the vernier scale division (VSD).
The smallest division on the main scale is 1 mm.
The vernier scale has 20 divisions coinciding with 19 divisions of the main scale.
Therefore, the value of one vernier scale division (VSD) can be calculated as:
\[ VSD = \frac{19 \text{ MSD}}{20} = \frac{19 \times 1 \text{ mm}}{20} = 0.95 \text{ mm} \]
Step 2: Calculate the least count (LC) of the vernier callipers.
Least Count (LC) = MSD - VSD = 1 mm - 0.95 mm = 0.05 mm.
Step 3: Zero Error Calculation: Since the zero of the vernier scale is on the right side of the zero of the main scale, it indicates a positive zero error. The number of divisions on the vernier scale that coincide and the value of the coinciding division can be used to determine the error. In this case, the 12th division of the vernier coincides, which indicates a positive zero error of **0.60 mm** (or 12 x LC).
Therefore, the type of zero error is positive, and its value is +0.60 mm.
The smallest division on the main scale is 1 mm.
The vernier scale has 20 divisions coinciding with 19 divisions of the main scale.
Therefore, the value of one vernier scale division (VSD) can be calculated as:
\[ VSD = \frac{19 \text{ MSD}}{20} = \frac{19 \times 1 \text{ mm}}{20} = 0.95 \text{ mm} \]
Step 2: Calculate the least count (LC) of the vernier callipers.
Least Count (LC) = MSD - VSD = 1 mm - 0.95 mm = 0.05 mm.
Step 3: Zero Error Calculation: Since the zero of the vernier scale is on the right side of the zero of the main scale, it indicates a positive zero error. The number of divisions on the vernier scale that coincide and the value of the coinciding division can be used to determine the error. In this case, the 12th division of the vernier coincides, which indicates a positive zero error of **0.60 mm** (or 12 x LC).
Therefore, the type of zero error is positive, and its value is +0.60 mm.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The main scale division of vernier calliper is equal to 1 mm. 19 division of main scale are
equal i…
1 cm on the main scale of the vernier callipers is divided into ten equal parts. If 20 division
of …
A spherometer has 100 equal divisions marked along the periphery of its disc, and one full
rotation…
The vernier scale of vernier callipers has 10 divisions. One centimeter on the main scale is
divide…
A vernier caliper has 20 divisions on the vernier scale which coincide with 19 divisions on
the mai…
The main scale of vernier calliper is divided into 0.5 mm and its least count is 0.005 cm. The
numb…