A thin converging lens of focal length 
forms a sharp image of an object on a screen placed at a distance of 
from the lens. Later the screen is moved closer to the lens by a distance 
. The distance through which the object is to be shifted so that its image on the screen is sharp again is
A
towards the lens B
away from the lens C
towards the lens D
away from the lens
Text Solution
Verified by ExpertsThe correct answer is:
D
Now, By lens formula, 
When the screen shift upto by 
, then the screen will be at 
.
For to get sharp image, object has to be a 
.
So, the distances is 
.
This is the distance through which the object shifted from the lens.
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
The image formed by a convex mirror of focal length is a quarter of the size of the object. The di…
An object is placed infront of a spherical concave mirror between the focal point and the radius of…
An object is placed at a distance of in front of a concave mirror of focal length . The image pro…
A girl of height with her eye level at stands in front of plane mirror of height fixed to a wall…
An object is placed at to the left of a concave mirror of radius of curvature as shown in the fi…
Consider a light source placed at a distance of along the axis facing the convex side of a spheric…