A very small mass m is fixed to one end of a massless spring of constant k and normal length l. The spring and the mass are rotated about the other end of the spring with angular speed ω ω . Neglect the effect of gravity. Extension in the spring is
A
Zero
B
C
ml ω ω 2
D
Text Solution
Verified by ExpertsThe correct answer is:
D
Here spring force = centripetal force
∴ ∴ kx = m (l + x) ω ω 2 (where x is the extension in the length of the spring)
i.e., x = 
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